Can you please help me answer all 5 questions. 2. (1 pt) Given a 19 bit address

Question

Can you please help me answer all 5 questions.

2. (1 pt) Given a 19 bit address bus, how many unique addressed can be accessed? 3. (1 pt) Given a hard disk with 4.3 TB of data, what size address bus would be required to access all of the bytes? Show your work. 4. (1 pt) What is the largest power of two alignment for the following decimal number? (Hint: Convert to hex first.) 49088 5. (1 pt) What is the base logic operation for the addition operation? 6. (1 pt) Determine the number of 16K blocks in 2GB of memory

Explanation / Answer

2
19 bit address bus can create 2^19 addresses

3
4.3 TB = 4.3 * 1024 GB = 4.3 * 1024 * 1024 MB = 4.3 * 1024 * 1024 * 1024 KB = 4.3 * 1024 * 1024 * 1024 * 1024 B
So number of address line required is ceil (lg(4.3 * 1024 * 1024 * 1024 * 1024)) = ceil(42.2) = 43bit address bus required

4
49088 = BFC0 in hex

So largest power of 2 is 15

5
XOR is the base logic operation for addition

6
No of 16K block in 2GB is
2GB/ 16K = 2*1024MB/16K = 2*1024*1024K/16K = 2^21/2^4 = 2^17 blocks

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