Study carefully the following code: { ... } //Producer while (1) { while (((in +

Question

Study carefully the following code: { ... } //Producer while (1) { while (((in + 1) BUFFER_SIZE) - out): // do nothing buffer[in] =: in (in + 1) % BUFFER_SIZE } //Consumer while (1) { while (in -- out): nextconsumed = butter[out]: out= (out + 1) % BUFFER_SIZE } a. State and explain the effect of assigning a value of 1 to BUFFER_SIZF? b. Suppose your friend rewrote the producer code and called it "MyVersionOfProducer However, after carefully studying it, you found a problem/issue in this version. Explain the issue with an example. //Producer while (1) { while (in == out): // do nothing buffer[in] = nextproduced: in = (in + 1) % BUFFER_SIZE }

Explanation / Answer

a) in this case there will be no difference in the output because the outer while condition is

ie while(1) will always be true

because Basically before each iteration the condition is evaluated to be TRUE or FALSE. In C TRUE is represented by non-zero value and FALSE by zero. while (1) indicates an always TRUE condition so any loop with having this statement will run forever. This is also known as infinite loop.

so the producer loop won't exit;

and now if you assign a value of 1 to BUFFER_SIZE

in the inner while

ie while(((in + 1) % BUFFER_SIZE) == out)

     here (in +1) % BUFFER_SIZE   will always return 0 (zero) if you assign BUFFER_SIZE to 1

because anynumber can be divided by 1 so the mod will be zero

b )

     in this case the difference is in the while loop

ie while(in == out)

so the loop will wait untill in != out   ie in not equal to out

only after that the next two lines execute

if any thing wrong please replay with the full code and make sure it's readability

instead of screen shot like this please paste the code

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