This daily will allow you to practice more with the bit wise operators and shift

Question

This daily will allow you to practice more with the bit wise operators and shifts. Consider the following main program: #include void set flag(int' flag_holder, int flag position); int check flag(int flag holder, int flag_position); int main(int argc, char* argv[]) int flag-holder = e; int i; set flag(&flag; holder, 3); set flag(&flag;_holder, 16); set flag(&flag;_holder, 31); for (i-31;-e; i) printf(Xd", check flag(flag holder, i)): printf(" ") printf("n" return e Write the code for the definition of set flag and check flag so that the output of your program looks like the following: ress any key to cont inue You can think of the set flag function as taking an integer and making sure that the n bit is a 1. The check flag function simply returns an integer that is zero when the nth bit is zero and 1 when it is 1. You may find the shifting

Explanation / Answer

Given below is the completed program with output. If it helped, please don't forget to rate it . Thank you very much.

#include <stdio.h>

void set_flag(int* flag_holder, int flag_position);
int check_flag(int flag_holder, int flag_position);

int main(int argc, char* argv[])
{
int flag_holder = 0;
int i;

set_flag(&flag_holder, 3);
set_flag(&flag_holder, 16);
set_flag(&flag_holder, 31);

for(i = 31; i >= 0; i--)
{
printf("%d", check_flag(flag_holder, i));
if(i % 4 == 0)
{
printf(" ");
}
}

printf(" ");
return 0;
}

void set_flag(int* flag_holder, int flag_position)
{
int value = 1 << flag_position; //create a value with specified bit set
*flag_holder = *flag_holder | value; //change only the specified bit by ORing
}
int check_flag(int flag_holder, int flag_position)
{
int value = 1 << flag_position; //move 1 to the specified position
int bit = flag_holder & value; //extract the bit

if(bit == 0)
return 0;
else
return 1;

}

output

1000 0000 0000 0001 0000 0000 0000 1000

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