Please answer this for me Utah Valley University PH x C WWW saplinglea rning com
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Please answer this for me
Utah Valley University PH x C WWW saplinglea rning com /ibiscms/mod/ibis/view.php?id 31118882 Due Date: 2/28/2014 11:55 PM Gradeb Attempts Score Print HCalculator Periodic Table 00 5 of 5 Map 00 00 Two thin disks are attached as shown to the right. The angle 8 30.8 and the masses and radii of the disks are listed in the table below. Disk radius (cm) Mass (kg) A 183 0656 E 520 0.245 What is the moment of inertia of this composite object about an axis perpendicular to the screen, through point p? kg. m o OUS Give Up & V solution Check A Next Hint ight D 20 2014 Sap about us careers partners privacy policy terms & conditions contact us help O Assignment Information Available From: Not Set 2/28/2014 11:55 PM Due Date Points Possible: 25 Grade Category: Graded Description: You can check your answers. You can view solutions when you complete or give n any question. You can keep trying to answer each question u you get it right or give up. You lose 5% of the points available to each answe in your question for each incorrect attempt at tha O Help With This Topic Web Help & Videos O Technical Support and Bug Reports 5:03 PM 2/28/2014.Explanation / Answer
distane between the centers AB = r1 + r2 = 18.3 + 5.2 = 23.5 cm
AP = 18.3 cm
moment of inertia of a disc about its center = mr^2/2
about a point which at a distace x from center = mr^2/2 + mx^2
here x = .183 m for A
MA = 1.5mr^2 = .033 kg.m^2
x = sqrt (18.3^2 + 23.5^2 + 2*18.3*23.5|cos(18030.8)|) = 22.92 cm
MB = .5*.245*.052^2 + .245*.2292^2 = .013
total moment of inertia = .046 kg.m^2