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Time (s) X(m) Y(m) X Velocity Y Velocity .5 0.821778978432 2.79406026606 -0.1952

ID: 3894573 • Letter: T

Question

Time (s)

X(m)

Y(m)

X Velocity

Y Velocity

.5

0.821778978432

2.79406026606

-0.195290988933

0.716066959422

.6

.799245402786

2.87067442325

-0.153979433582

0.645336569199

.7

.785725257399

2.92926171993

-0.102152209596

0.561086033589

.8

.781218542269

2.98784901661

-0.0688525922521

0.430641667904

.9

.77671182714

3.01488930739

-0.0701044575657

0.284173426204

1

.763191681752

3.04643631329

-0.0400596900376

0.116423474172

1.1

.763191681752

3.04643631329

0.0338003634692

-0.115171608858

1.2

.77671182714

3.01488930739

0.0550820738017

-0.275410369008

1.3

.77671182714

2.98334230148

0.053830208488

-0.364292806279

1.4

.781218542269

2.95179529558

0.101401090408

-0.522027835802

1.5

.799245402786

2.87518113838

0.130694738748

-0.637700190786

1.6

.808258833045

2.8165938417

0.156483164209

-0.692907451119

1.7

.830792408691

2.73547296938

0.192787258306

-0.758630380087



Graph based upon data yielded this equation: Y = A(t-t0)^2 + B(t-t0) + Ct0

t0 =.5

A = -.7647

B = .8604

C = 2.794


A. Use the kinematics equation you found to determine the vertical component of the acceleration of the astronaut, ay.

B. Do the same thing as above and identify v0y and initial position y0.

C. Use the tabulated data to find the height, h, of the astronaut

Time (s)

X(m)

Y(m)

X Velocity

Y Velocity

.5

0.821778978432

2.79406026606

-0.195290988933

0.716066959422

.6

.799245402786

2.87067442325

-0.153979433582

0.645336569199

.7

.785725257399

2.92926171993

-0.102152209596

0.561086033589

.8

.781218542269

2.98784901661

-0.0688525922521

0.430641667904

.9

.77671182714

3.01488930739

-0.0701044575657

0.284173426204

1

.763191681752

3.04643631329

-0.0400596900376

0.116423474172

1.1

.763191681752

3.04643631329

0.0338003634692

-0.115171608858

1.2

.77671182714

3.01488930739

0.0550820738017

-0.275410369008

1.3

.77671182714

2.98334230148

0.053830208488

-0.364292806279

1.4

.781218542269

2.95179529558

0.101401090408

-0.522027835802

1.5

.799245402786

2.87518113838

0.130694738748

-0.637700190786

1.6

.808258833045

2.8165938417

0.156483164209

-0.692907451119

1.7

.830792408691

2.73547296938

0.192787258306

-0.758630380087

Explanation / Answer

A) from equation A = 1/2 a
so a = 2*-0.7647=-1.5294

B) Voy = B = 0.8604

y0 = C = 2.794

D) F = m a = (180/32+190/32)*1.5294= 17.68 lb downwards