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I keep getting 82.8 Amps and it\'s wrong... Please need a good explanation. In t

ID: 3897348 • Letter: I

Question

I keep getting 82.8 Amps and it's wrong... Please need a good explanation.



In the figure (Figure 1) the top wire is 1.3?mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 91A in each. I keep getting 82.8 Amps and it's wrong... Please need a good explanation.



In the figure (Figure 1) the top wire is 1.3?mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 91A in each. I keep getting 82.8 Amps and it's wrong... Please need a good explanation.



In the figure (Figure 1) the top wire is 1.3?mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 91A in each. I keep getting 82.8 Amps and it's wrong... Please need a good explanation.



In the figure (Figure 1) the top wire is 1.3?mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 91A in each. Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Provide Feedback Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining ICu =
A ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Incorrect; Try Again; 5 attempts remaining Incorrect; Try Again; 5 attempts remaining Provide Feedback of 1 I keep getting 82.8 Amps and it's wrong... Please need a good explanation.



In the figure (Figure 1) the top wire is 1.3?mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 91A in each. Part A Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu =
A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Provide Feedback of 1

Explanation / Answer

The density of copper is 8.92 g/cm3 which is 8920 kg/m3


Lets consider 1 meter of wire each so that the mass of the upper wire is...


? = m/V where the volume is ?r2l


The volume is ?(6.5 X 10-4)^2*1


  


8920 = m/1.327 X 10-6 kg/m


mass is .0118 kg/m



Now, that will provide a weight acting down. The two upward components of the force will act.



The force between current carrying wires is...


F/l = ?oI1I2/2?r


The vertical component will be...


F = (?oI1I2l/2?r)(sin 60)


Since we have two of those,


2(?oI1I2l/2?r)(sin 60) = mg


Start plugging in numbers (I am assuming that the diameter given is in mm and the current is 79 A. Units were not supplied in your question. If those are not the correct units, the answer will be off, but the procedure valid. Just plug in your correct units if needed).


(2)(4? X 10-7)(91)(I2)(sin 60)(1)/(2)(?)(.038) = (.0118)(9.8)


I2 is the only unknown left, so you can solve for it.


I2 = 139.87 Amps