Please show work LON-C. X Homewo... X c https://s3.lite.msu.edu/res/sc/gblanpied
ID: 3899510 • Letter: P
Question
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LON-C. X Homewo... X c https://s3.lite.msu.edu/res/sc/gblanpied/courses/usclib/hrw8/chapter 28/hrw8c28p68.problem?symb uploaded%2fsc Course Contents HW 6 An electron in a TV camera tube is moving Notes W Bookmark Evaluate Communicate Priin (8c28p68) An electron in a TV camera tube is moving at 8.00x106 m/s in a magnetic field of strength 73 mT Without knowing the direction of the field, wha say about the greatest and least magnitude of the force acting on the electron due to the field? Maximum force? Submit Answer Tries 0/15 Minimum force? Submit Answer Tries 0/15 At one point the acceleration of the electron is 4.172x10 m/s2 What is the angle between the electron velocity and the magnetic field? (deg) Submit Answer Tries 0/15 This discussion is closed Send S A LTEExplanation / Answer
F = qvBsink
magnitude of force will be greatest when sink =1
magnitude of force will be minimum when sink =0
F max = qVB
= 1.6*10^-19*8*10^6*73*10^-3
= 934.4 *10^-16 N
Fmin = 0
ma = qvBsink
934.4*10^-16sink = (9.1*10^-31*4.172*10^16)
sink = 0.4063
k = 23.97 degrees