Please use Java. Thank you! 1. Queues and Stacks:Write a method called isConsecu
ID: 3904284 • Letter: P
Question
Please use Java.
Thank you!
1. Queues and Stacks:Write a method called isConsecutive() that takes a stack of integers as a parameter and that returns whether or not the stack contains a sequence of consecutive integers starting from the bottom of the stack (returning true if it does, false if it does not). (20 pts) Consecutive integers are integers that come one after the other as in 5, 6, 7, 8, 9,etc... So if a stack s stores the following values: bottom [3, 4, 5, 6, 7, 8, 9, 10] top the following call: ?sConsecutive ( s ) ; should return true If the stack had instead contained this set of values: bottom [3, 4, 5, 6, 7, 8, 9, 10, 12 top then the call should return false because 10 and 12 are not consecutive. Notice that we look at the numbers starting at the bottom of the stack. The following sequence of values would be consecutive except for the fact that it appears in reverse order so the method should return false: bottom [3, 2, 1] top Your method must restore the stack so that it stores the same sequence of values after the call as lt did before. Any stack with fewer than twovalues should be considered to be a list of consecutive integers. You are to use one queue as auxiliary storage to solve this problem. You may not use peek() or any iterators.Explanation / Answer
Program
import java.util.*;
public class Consecutive {
public static void main(String[] args)
{
Stack<Integer> s=new Stack<Integer>();
s.push(1);
s.push(2);
s.push(3);
s.push(4);
System.out.println(isConsecutive(s));
}
public static boolean isConsecutive(Stack<Integer> s) {
if(s.size() < 2)
return true;
Queue<Integer> q = new LinkedList<Integer>();
int next = s.pop();
q.add(next);
boolean consecutive = true;
while(!s.isEmpty()) {
int n = s.pop();
if(n + 1 != next)
consecutive = false;
next = n;
q.add(n);
}
while(!q.isEmpty())
s.push(q.remove());
while(!s.isEmpty())
q.add(s.pop());
while(!q.isEmpty())
s.push(q.remove());
return consecutive;
}
}