Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Class \"C\" Subnetting IP Address 200.61.78.0 Borrow 3 bits What is the subnet m

ID: 3904889 • Letter: C

Question

Class "C" Subnetting IP Address 200.61.78.0 Borrow 3 bits What is the subnet mask? How many possible subnets are created? How many usable subnets are created? How many possible host on each subnet? How many usable host on each subnet? What is the total number of usable host for this network? IP Address 196.45.204.0 Borrow 4 bits What is the subnet mask? How many possible subnets are created? How many usable subnets are created? How many possible host on each subnet? How many usable host on each subnet? What is the total number of usable host for this network? IP Address 213.9.125.0 Borrow 5 bits What is the subnet mask? How many possible subnets are created? How many usable subnets are created? How many possible host on each subnet? How many usable host on each subnet? What is the total number of usable host for this network?

Explanation / Answer

Solution:- Please find the description below.

Class C subnetting starts from 255.255.255.0 and it is generally done in order to avoid wastage of IPs as well as easy to administrate.

For class C

IP ADDRESS: - 200.61.78.0/24

Now 3 bits borrowed.

Therefore, subnet becomes 27

IP can be written as 200.61.78.0/27

27 can be broken down into bits and it looks something like this.

27 -> 11111111.11111111.11111111.11100000

So here 3 bits borrowed and 5 bits left over.

------------------------------------------------------------------------------------------------------------------------------

2) IP address = 196.45.204.0

Now 4 bits borrowed

Therefore, subnet become 28

So the IP looks like this 196.45.204.0/28

28 -> 11111111.11111111.11111111.11110000

Here 4 bits borrowed and 4 bits left out.

------------------------------------------------------------------------------------------------------------------------------------------------

3) IP address = 213.9.125.0

Now 5 bits borrowed.

Therefore, subnet becomes 29

So, IP looks like 213.9.125.0/29

29 -> 11111111.11111111.11111111.11111000

Here 5 bits borrowed and 3 left out.