CIS150 U2 Lab_IP Addressing Basics Re. Table Tools Layout References Mailings Re
ID: 3907724 • Letter: C
Question
CIS150 U2 Lab_IP Addressing Basics Re. Table Tools Layout References Mailings Review View Help Design Layout Tell me what you want to do With the following IP host addresses, indicate the following: .Class of each address Network address or ID Host portion Broadcast address for this network Default subnet mask The host portion will be all zeros for the network ID. Enter just the octets that make up the host. portion will be all ones for a broadcast. The network portion of the address will be al ones for the subnet mask. Fill in the following table: Address Network Address Host IP Address 216.14.55.137 123.1.1.15 150.127.221.244 94.125.35.199 175.12.239 244 Network Broadcast Address Default Subnet Mask Class Step 4: Given an IP address of 142.226.0.15 and a subnet mask of 255.255.255.0, answer the following questions: . What is the binary equivalent of the second octet? . What is the class of the address?Explanation / Answer
solution: -
Ip address: - 216.14.55.137
IP: - 123.1.1.15
IP: - 150.127.35.199
IP: - 194.125.35.199
IP: - 175.12.239.244
142.226.0.15 with subnet mask 255.255.255.0: - It is a classless IP address and it is done to reduce wastage of IP. The binary bit is 24, that means 24 1’s are there and 8 0’s are there.