Problem 1: write a C program that reads an integer n, generate cube of the integ
ID: 3929380 • Letter: P
Question
Problem 1: write a C program that reads an integer n, generate cube of the integer n read by calling the cube function. Continue the computation while n! = 0.
Output:
· Enter a value 7
The Cube of 7 is 343
· Enter a value 0
The Cube of 0 is 0
Problem 2: Write a C program to read 5 real numbers (Use an array of size 5 to store elements) and then print them in order and reverse order. Define functions ReadDepositArray, ShowDepositArrayInorder, and ShowDepositArrayReverse to perform this task.
Output:
Enter 5 deposits values:
15.5 45.2 33.12 88.88 11.12
Your deposits are:
Deposit [1]: 15.5
Deposit [2]: 45.2
Deposit [3]: 33.12
Deposit [4]: 88.88
Deposit [5]: 11.12
Your deposits <reversed> are:
Deposit [5]: 11.12
Deposit [4]: 88.88
Deposit [3]: 33.12
Deposit [2]: 45.2
Deposit [1]: 15.5
Explanation / Answer
1.
#include <stdio.h>
int cube(int);
int main()
{
int n,c;
printf("Enter the number: ");
scanf("%d",&n);
c=cube(n);
printf(" %d",c);
}
int cube(int a)
{
while(a!=0)
return a*a*a;
}
2.
#include<stdio.h>
#include<stdlib.h>
#define MAXSIZE 5
int main()
{
float a[MAXSIZE];
int i,n;
printf("Enter number of values :");
scanf("%d",&n);
printf("Enter real numbers :");
for(i=0;i<n;i++)
{
scanf("%f",&a[i]);
}
inorder(n,a);
printf(" ");
reverseorder(n,a);
}
int inorder(int n,float a[5])
{
int i;
for(i=0;i<n;i++)
{
printf(" %f",a[i]);
}
}
int reverseorder(int n,float a[5])
{
int i,j,temp;
j=n;
if(n%2==0)
{
for(i=0;i<n;i++)
{
a[i]=a[j];
j--;
}
}
else
{
for(i=0;i<n;i++)
{
if(j==((n/2)+1))
{
continue;
}
else
{
a[i]=a[j];
j--;
}
}
}
for(i=0;i<n;i++)
{
printf(" %f",a[i]);
}
}