An atmospheric scientist interested in how NO is converted into NO2 in urban atm

Question

An atmospheric scientist interested in how NO is converted into NO2 in urban atmospheres carries out two experiments to measure the rate of this reaction. The data are tabulated below:

P.S. A lot of people have posted this question but no one is getting the right answer. Please help!

Experiment A: [NO 9.63 x 103 M, LO,lo, 4.1 x 10 M 0 3.0 6.0 9.0 12.0 t(s) [o2010 M) 4.1 2.05 1020.51 0.25 Experiment B: [NOla 4. 1 x 10 M, Lozlo 9.75 x 10.3M (102 s) 0 1.00 2.00 3.00 4.00 [NO](10" M) 4.12.05 143 1.02 0.82 What is the rate law and rate constant for this reaction?

Explanation / Answer

Ans. For calculating the rate law w need to find the order of reaction with respect to NO and O2 we will plot each Experiment data and plot graph of [NO], ln[NO] and 1/[NO] vs time and the graph which gives straight line will be the order of reaction with respect to [NO]. similar is the case for [O2]

The data for these cases is given as below

In the Exp A the graph between ln[O2] and t is straight therefore first order wrt [O2]

t1 [O2] ln[O2] 1/[O2] 0 4.1 1.410987 0.243902 3 2.05 0.71784 0.487805 6 1.02 0.019803 0.980392 9 0.51 -0.67334 1.960784 12 0.25 -1.38629 4

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