The combustion of ethylene proceeds by the reaction: C_2H_4(g) + 3O_2 (g) righta

Question

The combustion of ethylene proceeds by the reaction: C_2H_4(g) + 3O_2 (g) rightarrow 2 co_2 (g) + 2H_2O (g) When the rate of disappearance of O_2 is 0.19Ms^-1, what is the rate of appearance of co_2? 0.19 Ms^-1 0.093 Ms^-1 0.84 Ms^-1 0.42 Ms^-1 0.56 Ms^-1 An exothermic one-step reaction has an activation energy of 30 kj/mol and a deltaH of -15 kj/mol in the forward direction. A catalyst lowers the activation energy of both the forward and reverse directions by 10kj/mol. What is the activation energy of the reverse catalyzed reaction? 30 kJ/mol 55 kJ/mol 45 kJ/mol 35 kJ/mol 15 kJ/mol

Explanation / Answer

4)

From the coefficients of the equation, the mole ratio of O2:CO2 is 3:2.
The rates will have the same ratio

So, if O2 is 0.19 M/s, CO2 will be 0.19*2/3 = 0.127 M/s.

5)

Catalysts affect both processes by the same extent, 10kJ/mol in this case. It helps attain equilibrium faster but does not alter the amount of products or reactants at equilibrium. So answer is 30 KJ/mol.

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