What are the \"products\" of the reaction? ( Hint: see the right hand side of th

Question

What are the "products" of the reaction? ( Hint: see the right hand side of the chemical equation above) The chemical equation above is HKC8H4O4 + NaOH -------> NaKC8H4O4 + H2O. Please help. Thank u I'm a little confused. rockroom Explorer lrydium Solutions H20 Solutions A 1M NaOH A 0.500M KHP Phenolphthalein D Problem Descriptio Problem Description Workbench 50mL Buret 0,500M KHP Workbench 1 Problem Description Transfer amount (mL): S Solution Info Name: 0.500M KHP Volume: 62.0 mL Aqueous O Solid Molarity T pecies 6.491e-7 OH 1.556e-8 KHP 1.881e-2 1.828e-1 Phenolphthale 8.063e-7 Phenolphthalei... 1.151e-10 1.828e-1 Na 25.00C Phenolphthalein Pour from 50mL Buret to 0.500M KHP

Explanation / Answer

In case of any reaction,

left side of the arrow are reactants and right side of the arrow are products

In your case ,products will be NaKC8H4O4 and H2O

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