A member of the tardus migratorius is flying across road at an average speed of

Question

A member of the tardus migratorius is flying across road at an average speed of 30.50 miles per hour. The road is 4.000 meters in width. How many seconds will it take the feathered creature to traverse the road if it follows the most direct path? A member of the tardus migratorius is flying across road at an average speed of 30.50 miles per hour. The road is 4.000 meters in width. How many seconds will it take the feathered creature to traverse the road if it follows the most direct path? A member of the tardus migratorius is flying across road at an average speed of 30.50 miles per hour. The road is 4.000 meters in width. How many seconds will it take the feathered creature to traverse the road if it follows the most direct path?

Explanation / Answer

V avg = 30.5 mi/h

W = 4 m

time required in seconds...

change V to m/s

1609.4 m = 1 mi

V avg = 30.5 mi/h * 1609.4 m / mi = 49086.7 m per h

change h to s, 1 h = 3600 s

so

V = 49086.7 m/h * 1 h / 360 s= 13.63472 m/s

so..

V = D/T

t = D/V = 5/13.63472

t = 0.3667 seconds will require to cross the street

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