In your experiment the product is characterized using IR spectroscopy, because t
ID: 480589 • Letter: I
Question
In your experiment the product is characterized using IR spectroscopy, because that is easy for that you to do in the lab. However, NMR spectroscopy is usually much better for characterizing organic material structures. Describe IN WORDS, how you would distinguish the product bromide form the starting material alcohol using proton NMR spectroscopy. You can use the provided structures in your explanation, Do not attempt to distinguish them based on absolute values of chemical shifts (i.e., don't make statements such as "the chemical shift of protons X should be 3.86 in the bromide and 3.65 in the alcohol")there is another much simpler way of distinguishing the structures.Explanation / Answer
The molecules are Butanol ( CH3CH2CH2CH2OH) and Butyl bromide( CH3CH2CH2CH2Br)
Butanol has an –OH peak and this –OH appears as a singlet at about 4.65 delta in the 1HNMR spectrum of Butanol.This -OH peak is absent in the 1HNMR spectrum of Butylbromide.
If –OH peak is absent in the 1HNMR spectrum of the product Butyl bromide, it means that the starting material Butyl alcohol is completely converted to the product.