Please answer all. These are inorganic chemistry questions. Please also explain.

Question

Please answer all. These are inorganic chemistry questions. Please also explain.

C. What is the magnetic moments of the following species considering both the high spin and low spin cases.

Compound

#unpaired electrons

if low spin

# unpaired electrons

if high spin

[Cr(H2O)6]2+

[FeCl6]4-

[RhF6]3-

CpW(CO)3CH3

                       

D. Fe(H20) 6+2 is paramagnetic whereas Fe(CN) 6-4 is diamagnetic. Explain the difference. Which would have a longer max? Explain your prediction.

Compound

#unpaired electrons

if low spin

# unpaired electrons

if high spin

[Cr(H2O)6]2+

[FeCl6]4-

[RhF6]3-

CpW(CO)3CH3

Explanation / Answer

BM = Bhor magneton

Fe(H2O)6+2 is high spin complex it has 4 unpaired electron therefore the complex paramagnetic and it will have longer lamda max

Fe(CN)6-4 is low spin complex it has no unpaired electron therefore the complex is diamagnetic

compound magnetic moment if low spin magnetic moment if low spin [Cr(H2O)6]2+ 2.83 BM 4.90 BM [Fe(Cl)6]4- 0 4.90 BM [RhF6]3- 0 4.90 BM [CpW(CO)3CH3 2.83 BM 4.90 BM

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