Can someone please help me in answering my Chemistry 1062 Rate Law Determination
ID: 486298 • Letter: C
Question
Can someone please help me in answering my Chemistry 1062 Rate Law Determination of the Crystal Violet Reaction LAB? I already did the experiment in the lab and below are the results and experiment procedure. Please help me with the data analysis problems which include this first page that range from questions 6-10 and the one that states on it data analysis which range from question 1-5. I am sorry that it is not well structured because it is my first time uploading here and I found it difficult to do.
Time (min) Trans (96T) Absorbance lov l in lovy 1/ov Rate 62.07 0.207 5.5E-06 -12.104 1.8 405 62.78 0.202 5.4E-06 -12.128 1 1.8E+05 .00 63.89 0.195 5.2E-06 12.167 1.9E+05 50 65.16 0.186 5.0E-06 12.212 2.0E 2.00 66.23 0.179 4.8E-06 12.250 2.1E+05 67.27 0.172 4.6E-06 12.289 2.2E+05 68.38 0.165 4.4E-06 12.331 2.3E+05 350 69.39 0.159 4.2E-06 12.370 2.4E+05 t t 400 70.28 0.153 4.1E-06 12.406 2.4E+05 71.20 0.148 3.9E-06 12.443 2.5E+05 6.00 72.09 0.142 3.8E-06 -12.481 2.6E+05 5.50 72.90 0.137 3.7E-06 12.515 2.7E+05 73.82 0.132 3.5E-06 12.556 2.8E+05 -12 400 6.50 74.70 3.4E-06 12.596, 3.0E+05 0.127 -12.600 3.3E-06 12.630 76.44 0.117 3.1E-06 -12.678 3.2Eros 12.800 77.07 0.113 3.0E-06 12.709 3.3E+05 E 13.000 8.50 77.78 2.9E-06 12.745 3.4E+05 0.109 13.200 0.105 78.50 2.8E-06 12.782 3.6E+05 79.24 -13400 0.101 2.7E-06 12.821 3.7E+05 79.81 0.098 2.6E-06 12.853 3.8E+05 13.600 2.5E-06 12.898 4.0E+05 0.094 13800 81.13 0.091 2.4E-06 12.928 4.1E+05 1.50 81.94 0.087 2.3E-06 12.977 4.3E+05 82.47 0.084 2.2E-06 13.010 4.5E+05 2.50 83.00 2.2E-06 13.044 4.6E+05 83.56 0,078 2.1E-06 13.080 4.8E+05 83.92 0.076 2.0E-06 13.105 4.9E+05 84,68 0.072 RUN 1 CV vs Time 10.00 Time (min) y -0.0743 x 12 108 0.9996 20.00 25.00Explanation / Answer
5. A linear plot is observed for lnK vs time graph . So, this is a first order reaction.
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6. You have a linear equation of with a general form y =mx + x . here m = slope
In the linear plote slope = -k
for run1 k = 0.0743/s
for run 2 k = 0.0274/s
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7.
(t1/2) = 0.693/k
(t1/2) run1 = 0.693/0.0743/s =9.33 sec
(t1/2) run1 = 0.693/0.0274/s = 25.3 sec
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8.
rate = k[CV+]
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9.
To calculate the rate in the excel sheet type =slope * [CV^+]
Rate should decrease as the comcentration of Cv is decreased