I knew a&b. Can anyone please answer c-e and 4? Explain all answers please. Than
ID: 486325 • Letter: I
Question
I knew a&b. Can anyone please answer c-e and 4? Explain all answers please. Thank You.
Not all of the following statements are correct. Indicate whether the statem correct or incorrect, then rewrite each incorrect statement to correct the error(s). The hydrolysis of t-BuCl proceeds faster when the OH^- in solution is high Correct? yes or no (circle one) If the temperature increases, the rate of reaction increases Correct? yes or no First-order rate constants get larger as temperature increases but second-order rate constants remain essentially unchanged. Correct? yes or no If temperature remains constant, each half-life in a first-order reaction is the same length of time, but they double each time for second-order reactions. Correct? yes or no The principal role of NaOH in this reaction is to catalyze the hydrolysis of t-BuCl. Its secondary role is to neutralize the HCl produced in the reaction. Correct? yes or no Which step in the reaction mechanism for the hydrolysis of t-BuCl is likely to have the greater activation energy? Explain your answer please.Explanation / Answer
C) Rate constants of any order have the same relation with temperature. It depends exponential to the reciprocal of the absolute temperature ( Arrhenius equation).
D) yes. For first order reaction the half life depends only on the reciprocal of the rate constant. So there won't be any change. For second order reaction, the half life is inversely proportional to the rate constant as well as the concentration. Hence each time, the concentration gets halved, the corresponding half-life get doubled.
E) Since the hydrolysis is first order reaction and solely depends on the concentration of t butyl chloride. So NaOH do not catalyse the reaction. However it neutralise the HCl formed.
4) The formation of carbocation step will have the highest activation energy. From a neutral molecule it is going to positively charged species . The energy of this tricoordinated species is higher compared to the neutral molecule. Hence for the formation of such a species high energy is required and this reflected in the greater activation energy.