The reaction below has an equilibrium constant K p=2.2×106 at 298 K. 2COF2(g)CO2
ID: 489303 • Letter: T
Question
The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)CO2(g)+CF4(g)
Calculate Kp for the reaction below.
COF2(g)12CO2(g)+12CF4(g)
Explanation / Answer
Kp for the reaction below.
COF2(g)1/2CO2(g)+1/2CF4(g)
Kp^(1/2)
(2.2 x 10^6)^(1/2)
=1483.24