Steady state. Michaelis and Menten assumed that the overall reaction for an enzy
ID: 490572 • Letter: S
Question
Steady state. Michaelis and Menten assumed that the overall reaction for an enzyme-catalyzed reaction could be written as: Using this reaction, what expression can be used to describe the rate of breakdown of the enzyme-substrate complex? What does the "steady state assumption", as applied to enzyme kinetics, imply? Write the expression of the steady state assumption. When k_2 is very small compared to k_1 and k_-1, what process is rate determining in product formation? Why is k_2 is very small compared to k_1 and k_-1?Explanation / Answer
ES is formed from reaction-1, decompose back to E and S throuh reaction-2 and also decomposed from reaction-3
Hence rate of ES = d[ES)/dt= K1[E][S]-K-1[ES]- K2[ES]
the net rate of formation of intermediate =0 is known as steady state assumption
when K2 is small, d(ES/dt)= K1[E][S]-K1-[ES] =0
or [ES] = (K1/K-1) [E][S]
when K2 is small, there is equilibrium between formation of ES from E and S and decompositino of ES back to E and S
since ES------>E+P is the rate limiting step, K2 is small.