Part B Calculate the molar translational internal energy of neon at STP using q(

Question

Part B

Calculate the molar translational internal energy of neon at STP using q(trans) = 1.70×1030 (Translational partition function for one mole of neon gas at T=273K and P=101325 Pa)

Part D

Calculate the molar translational entropy change S if the temperature of one mole of neon gas is increased to 500K and the volume is doubled from the value in part A.

Part E

In Chemistry 452 an equation for the molar entropy change of an ideal monatomic gas was given when the temperature changes from T1 to T2and the volume changes from V1 to V2.. Using this equation in terms of the inital and final tempertures, the initial and final volumes, and R, calculate the molar entropy change when the temperature of an ideal gas changes from T=273K to T=500K and the volume double

Explanation / Answer

Part B. As we know dU= nCv.dT

putting the value n=1 Cv=1.70 x1030 and dT=273

dU=478023 Joule

Part D. dS= nR ln V2/V1

dS= 2.303 nR log V2/V1

putting the value of V2= 2V and V1=V , R= .0821 n =1

dS= 2.303 X 2 X 8.314 = 38.294 Joule

Part E. dS= nR ln T1/T2

Putting the values

dS= 2.303 nR log T1/T2

dS= 2.303 X1 X8.314X 273/500

=9.215 Joule/ Kelvin

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