For sulfuric acid, K a1 is very large and K a2 is 0.012. Mastering chemistry Ch.

Question

For sulfuric acid, Ka1 is very large and Ka2 is 0.012.

Mastering chemistry Ch. 16.1 Acid Dase pt.1-Google Chrome https:// on.masteringchemistry.co itemview? assignment Problem 78486848 Kuebler CHM2046 Spring 2017 i Quantity ing Acid Ran t Quantifying Acid Rain Part A The presence of SO2 in the atmosphere and the sufurio acid that it produces result in If the pH of a 1.00-in rainfall over 1800 miles is 3.ro, how many kilograms of sulturic acid, Heso.. re present a that it is the only acid contributing to the pH? the phenomenon of acid rain. Uncontaminated rainwater is naturally acidi nd generally has a pH value nf abaut 56 The pH of acid rain is ahnut 4 This acidity has afforted For sulfuric acid. Kal is vary large and Ku is 0.012. orther United States, and C ducing fish Express your answer to two significant figures and includa tha appropriata units. populations and affecting other parts of the ecological network vithin the lakes and umoundin orests. The plT of most natural waters containing living organisms is between 65 and 85. but freshwater pH values are far below 6.5 in many parts of the continental United States. At pH levels below 4.0, all vertebrates, most invertebrales, and many m are destroyed. More than 300 lakes in New York State contain no fish, and 140 lakes in Value Units Ontario, Canada, are devoid of life. The acid ra at appears to have he Ohio Valley and Lints Me Answers Give Up Review Part ulful Subm el combustion decre e, in part because of the U.S. Clean Air A required that power plants reduce their sulfur emissions by 80%. incorrect, Try Again Activate

Explanation / Answer

Solution:

1mi²= 4014489600in²

1800mi²= 7226081280000in²

Volume of acid rain=1in x1800miles2= 7226081280000in3

10inch3=0.16L

7226081280000in3 =0.16x7226081280000in3/ 10in3= 43320772800L

pH solved for hydrogen ion molarity is =[H+] = 10-pH

[H+] =103.7= 5011.87M

1M solution of sulfuric acid has = (2+32+64=)98g of it in 1L

Therefore 5011.87 M has=98gx5011.87M/1M= 491163.26g in 1L

1L has = nearly 4.9kg

Therefore 43320772800L has=4.9kg x 43320772800L=212271786720kg

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