Assume three gas cylinders have been filled with three different gases at STP co

Question

Assume three gas cylinders have been filled with three different gases at STP conditions. The plant labeling system has messed up. but you know that the first two cylinders are pure Nitrogen (1) and pure Helium (2). A third cylinder contains an ideal gas of an unknown species. Under ideal conditions, cylinder 3 weighs 11.34027kg. Cylinder I has a weight of 11.34014kg under ideal conditions. Cylinder 2 weighs 0.2619 less grams. Use your knowledge of ideal gas behavior to figure out the identity of the unknown gas.

Explanation / Answer

Let the volume be 22.4 L. At STP,no of moles of moles of Nitrogen,

(1 atm ) (22.4 L) = n ( 0.082) (273 K)

n = 1 mole of N2 which is 28.0134 grams = 0.02801 kg

so weight of the Cylinder kg - 0.02801 kg = 11.31213 kg

Given the weight of the cylinder 3 is 11.34027 Kg ,

Weight of the unknown gas = 11.34027 kg - 11.31213 kg = 0.02814

so the unknown gas is also N2.

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