A decrease in volume will have what effect on the reaction below? C(s) + H_2O(g)

Question

A decrease in volume will have what effect on the reaction below? C(s) + H_2O(g) CO(g) + H_2(g) K decreases more CO(g) and H_2(g) are produced no effect K increases more H_2O(g) produced Consider the following reaction: CO(g) + 2H_2(g) CH_3OH(g) At room temperature, K is approximately 2 times 10^4, but at a higher temperature K is substantially smaller. Which of the following is true? The reaction is endothermic. The value of K_c for this reaction is smaller at all temperatures. At the higher temperature, more CH_3OH(g) is produced. The reaction is exothermic. The reaction becomes spontaneous at higher temperatures.

Explanation / Answer

35) Answer: A

Explanation:

If we decrease the volume, The pressure of the gas increases. In this equilibrium reaction products are completely gases, By decreasing the volume the equilibrium moves towards the lower pressure side that means left side or reactants side. Hence the products concentration decreases and the reactants concentration increases.

For the equilibrium constant K = (Gaseous products concentration) / (Gaseous reactants concentration)

K = [CO]. [H2] / [H2O]

Here CO and H2 concentration decreasing, Hence the K value decreases.

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