Anhydrous compounds are often used as a drying agent, or desiccant, because they
ID: 493941 • Letter: A
Question
Anhydrous compounds are often used as a drying agent, or desiccant, because they can easily absorb water, forming a hydrate. One important usage of anhydrous salts as a desiccant is between the two panes of double paned window. The desiccantis placed in the frame and absorbs moisture so that there should not be any condensation or fogging up between the two panes of the window However, the added desiccant will only be able to absorb a certain amount of water; once all of the desiccant is in the hydrated form, it will not be able to absorb more water. It also will not be easy to add more desiccant to the space between the window. Therefore, a good window desiccant will have a high capacity to absorb water per gram of the anhydrous desiccant. While working for Window World, you are part of a research team that needs to develop and implement a protocol for determining the capacity of desiccants, which can be expressed in terms of the mass of water that can be absorbed per gram of anhydrous salt. For each test you will be given an anhydrous salt and asked to determine how much water is present in the hydrate form. This project will be profitable only if you can find a material that has at least the absorption capacity of anhydrous calcium chloride (one of the most common desiccants so you will need to be able to make that comparison. l. In lab, you practiced the best way to measure the amount of water in a hydrate sample by heating off the water. Will you be able to use the same method of measuring the water when starting with an anhydrous sample? Why or why not? 2. How could you prepare a sample of your anhydrous desiccant to measure the amount of water present in the hydrate the same way you did in lab? Hint: Remember what happened when you added water directly to hydrates. How could you introduce water more slowly?Explanation / Answer
Q3.
for % of own weight:
MW of CaCl2 = 110.98 g/mol
MW of H2O = 18 g/mol
MW of CaCl2*6H2O = 110.98 + 18*6 = 218.98 g/mol
so...
218.98 /110.98 up to 1.973 times its weight
in %:
(218.98 -110.98 ) / 110.98 *100 % --> up to 97.31 % extra of its weight,
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