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The most intense line in the cerium spectrum is at 41B.7arn. Determine the frequ

ID: 496209 • Letter: T

Question

The most intense line in the cerium spectrum is at 41B.7arn. Determine the frequency of the radiation producing this line Express your answer using four significant figures in what part of the electromagnetic spectrum does in is line occur? Radio waves Microwaves. Infrared waves Visible Region Ultraviolet waves. X-radiation gamma-radiation Is it visible to the eye? If so. what color is it? If not. is this the at higher of lower energy than visible light? This lines visible, it's color is This lines visible, it's color is blue. This lines visible, it's color is violet. This lines visible, it's color is red. This lines visible it's energy is higher than the energy of visible light This lines visible it's energy is lower than the energy of visible light

Explanation / Answer

Ans. For an EMR,      c = v l                      - equation 1

            Where, c = speed of light = 299792458 m/s

                        v = frequency

                        l = wavelength     

# Part A. Given, l = 418 nm = 4.18 x 10-7 m

Putting the value of l in equation 1-

            299792458 m/s = v x (4.18 x 10-7 m)

            Or, v = (299792458 m/s) / (4.18 x 10-7 m)

            Or, v = 7.172 x 1014 s-1

Hence, frequency of the emr = 7.172 x 1014 s-1

# Part B. The wavelength of 418 nm is a part of visible spectrum (380 – 750 nm) of EMR. Thus, this line belongs to the visible region.

Correct option: D. visible region

# Part C. Yes, the line is visible to naked eye because it lies in visible spectrum of the EMR.

The wavelength of 418 nm is a part of violet region (380 – 450 nm) of visible spectrum. So, its color is violet.

Correct option. C.