Question
question 43 and 44
Write a balanced chemical equation for the reaction of aqueous solutions of (NH_4)_2SO_4(aq) + 2 NaOH(aq) rightarrow 2 NH_4OH(aq) + SO_3(g) + Na_2O(aq) (NH_3)_2SO_4(aq) + NaOH(aq) rightarrow 2 NH_3(g) + NaOHSO_4(aq) (NH_3)_2 SO_4(aq) + 2 NaOH(aq) rightarrow 2 NH_3(g) + Na_2SO_4(aq) + 2OH-(aq) (NH_4)_2SO_4(aq) + 2 NAOH(aq) rightarrow 2 NH^+_4 (g) + NaSO_4(aq) + 2 OH-(aq) (NH_4)_2SO_4(aq) + 2 NaOH(aq) rightarrow 2 NH_3(g) + 2 H_2O(l) + Na_2SO_4(aq) The net ionic equation for the reaction of calcium sulfite with nitric acid is CaSO_3(s) + 2H^+(aq) rightarrow Ca^2+ (aq) + SO_2(g) + H_2O(l). Ca^2+(aq) + CO^2-_3(aq) + 2H^+(aq) + 2NO^-(aq) rightarrow Ca(NO_3)_2(aq) + SO_2(g) + H_2O(l). CaSO_3(s) + 2HNO_2(aq) rightarrow Ca^2+(aq) + 2NO^-_2(aq) + SO_2(G) + H_2O(l). Ca(HSO_3)_2(s) + 2HNO_3(aq) rightarrow Ca^2+(aq) + 2NO^-_3(aq) + SO_2(g) + 2H_2O(l). CaSO_3(s) + 2HNO_3(aq) rightarrow Ca^2+(aq) + 2NO^-_3(aq) + SO_2(g) + H_2O(l). The oxidation number of chlorine is highest in
Explanation / Answer
Q43
ammonium sulfate + sodium hydroxide:
(NH4)2(SO4) + Na(OH)
note that:
NaOH is strong base and NH4+ is a weak acid:
NH4+ + OH- --> NH3 + H2O
so, NH# gas and H2O liquid forms, NA2SO4 remains in ionic
the ratio is:1:2 so:
2 mol of NH3 form:
ignore a, d,
2 mol of H2O form, ignore all
then, only E is true
Q44
net ionic equation contains only ions reacitng so
calcium sulfite --> CaSO3 and nitric acid --> HNO3
the overall reaction:
CaSO3 + 2 HNO3 = Ca(NO3)2 + H2O + SO2
so...
ignore b and d, since those reactants states of Calcium are not correct
ignore a, since 2H+ is not nitric acid
so only c and e can be
c can't be since NO2- is present this s nitrous acid, so
choose
E