Im having a hard time understanding how to set up and solve the following proble

Question

Im having a hard time understanding how to set up and solve the following problems..

In the pictures I determined the original Mass, molar mass, and moles of CuSO4× 5H2O) and (K2C2O4 x H2O).

In the pictures above, how do you determine...

1.)"Moles of K2[Cu (C2O4)2] x 2H2O formed based on CuSO4 x 5H2O"

2.)"Moles of K2[Cu (C2O4)2] x 2H2O formed based on K2C2O4 x H2O"

3.) Limiting reagent

4.) Theoretical moles of K2[Cu (C2O4)2] x 2H2O calculation

5.) Theoretical yield (mass) of K2[Cu (C2O4)2] x 2H2O calculation

In the Pictures above I was able to determine the mass of the watch glass and product.. But unsure of how to calculate:

6.) Percent Yield of the product (calculation)

And

7.) Percent error of the yield (calculation)

2 K2C20, H20 Kaso Use the periodic table in your lab manual to help with these calculations. Indicators for values that must be collected while you are in lab are italicized Molar Mass Mass Moles cuso. -5H20 2 Moles Mais Show your work 1.0170, 5.999 H Moles Mass Molar Mass

Explanation / Answer

1) & 2)
1) and 2) can be determined from the stoichometry of the reaction,
From the reaction it is clear that,
1 mole of CuSO4.5H2O gives 1 mole of K2[Cu (C2O4)2].2H2O
0.00407 mol of CuSO4.5H2O will give ? mol of K2[Cu (C2O4)2].2H2O
just cross multiply the numbers which is (0.00407*1 / 1)
Moles of K2[Cu (C2O4)2].2H2O produced based on CuSO4.5H2O = 0.00407 mol
Similarly,
2 moles of K2C2O4 . H2O gives 1 mole of K2[Cu (C2O4)2].2H2O
0.0136 mol of K2C2O4 . H2O will give ? mol K2[Cu (C2O4)2].2H2O
Moles of K2[Cu (C2O4)2].2H2O produced based on K2C2O4 . H2O = (0.0136*1 / 2) = 6.8*10-3 mol

3) Determining Limiting reagent,
From 1 and 2 we can say that CuSO4.5H2O will be limiting reagent (less number of moles)

4) Theoretical moles of K2[Cu (C2O4)2].2H2O =
     0.00407 mol * (1 mol of K2[Cu (C2O4)2].2H2O / 1 mol of CuSO4.5H2O) = 0.00407 mol

5) Theoretical mass of K2[Cu (C2O4)2].2H2O = 0.00407 mol * 575.3799 g/mol = 2.341796 gms
[ Molar mass of K2[Cu (C2O4)2].2H2O is 575.3799 g/mol ]

6) Percent yield = (actual yield in gm / theoretical yield in gm) * 100
   Percent yield = (1.279 gm / 2.341796 gm) * 100 = 54.616 %

7) Percent error of yield = (|actual yeild - theoretical yield| / theoretical yield) * 100
   Percent error of yield = (|1.279-2.341796| / 2.341796 ) *100 = 45.385 %
  

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