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Consider the following set of replicate measurements: 36.61 35.37 35.43 35.28 34

ID: 497184 • Letter: C

Question

Consider the following set of replicate measurements: 36.61 35.37 35.43 35.28 34.94 a) Apply the Q lest to this set to determine if one of the values should be discard, tor fi' observations the value of Q is 0.64 at the 90% confidence value. Do you keep or discard the outlier? Keep ____, Discard ____ After you perform the Q test answer the following questions: b) calculate the mean mean = ___ c) calculate the median median = ____ d) calculate the average deviation from the mean average deviation = ____ e) report the answer with correct significant figures and error (+/-) reported value = ____ +/- ____

Explanation / Answer

a) The N values comprising the set of observations under examination are arranged in ascending order:

34.94, 35.28, 35.37, 35.43, 36.61

Now calculate Q -

Q = X2 – X1 /Xn –X1

Q = 35.28 – 34.94/ 36.61 - 34.94

Q = 0.34 /1.67 = 0.203

We discard observation 36.61 as an outlier at a 90% confidence level

The corresponding Qexp = 0.20. Qexp is less than Qcrit value (= 0.64 at CL 90% for N=5).

b) The mean is the usual average, so add all set of data including outlier and then divide by N

(34.94 + 35.28 + 35.37 + 35.43 + 36.61) /5 = 35.53

Mean = 35.53

c) Median-

The median is the middle value, which is not affected by outliers.

Median- 35.37

d) Average deviation from mean

Mean = 35.53

Find the distance of each value from that mean-No minus signs

34.94 – 35.53 = 0.59

35.28 – 35.53 = 0.25

35.37 - 35.53 = 0.16

35.43 – 35.53 = 0.10

36.61 – 35.53 = 1.08

Add up all of the values and divide by N

Average deviation = (0.59 + 0.25 + 0.16 + 0.10 + 1.08)/5

                                  = 0.436

e) Correct significant figure = 0.44