Nominal EG Actual Mass EG (g) Mass Soln (g) Actual Mass Molality 10% 2.465 24.73

Question

Nominal EG Actual Mass EG (g) Mass Soln (g) Actual Mass Molality 10% 2.465 24.73 9.980 1.783724888 10% 2.465 24.73 9.980 1.783724888 8% 2.019 25.021 807 1.414178948 8% 2.019 25.021 807 1.414178948 2.630281949 14% 3.51 25.01 14.034. 2.630281949 149% 3.51 25.01 14.034. 69% 1508 24.997 6.03 1.034357009 69% 1508 24.997 6.03 1.034357009 0.03 0.753 25.021 3.01 0.4 99913239 0.03 0.753 25.021 3.01 0.4 99913239 25.104 1.189507227 25.102 1.189608999 1.726 2.228127445 12% 3.040 25.022 12.15 2.228127445 12% 3.040 25.022 12.15 25% 0.494 24.999 1980 0.324792424 25% 0.494 24.999 1980 0.324792424 25.014. 0.668821227 49% 997 3.99 0.668821227 49% 997 25.014. 3.99 16% 25.020 3.068658173 4.003 15.99 16% 3.068658173 4.003 25.020 15.99 24.998 0.844470593 5% 1.245 4.9800 0.844470593 5% 1.245 24.998 4.9800

Explanation / Answer

Solution :-

Molarity = moles of solute / kg solvent

Mass of solvent = (mass of solution) - (mass of solute EG)

Therefore sample calculation for the trial 1 are as follows

Trial 1

mass of solute = 2.465 g EG  

Mass of solent = 24.73 g - 2.465 g = 22.265 g = 0.022265 kg

Moles of solute EG = 2.465 g / 62.0678 g per mol

                       = 0.039715 mol

Molality = moles of EG / kg of solvent

             = 0.039715 mol / 0.022265 kg

             = 1.7837 m

So using this method find the mass of solvent for each trial and then use it in kg to calculate the molality.

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