I\'m pretty sure that I synthesized butyl acetate from 1-butanol, but I need hel

Question

I'm pretty sure that I synthesized butyl acetate from 1-butanol, but I need help with analyze the 1H-NMR based on chemical shift, splitting, and integration.

I think the peak at 4.1ppm have RCOO-CH with three neighboring hydrogens, peak at 3.8 have HC-COOR with two neighboring hydrogens, peak at 1.7 have R3CH3 with three neighboring hydrogens, peak at 1.4 have CH with a hydrogen, and peak at 1.0 have R3CH3 with three neighboring hydrogens. Is it right...? I'm not sure about this because I'm bad with reading the NMR data. Please give me the corrct reading of this H-NMR and explain this in details so I can understand it.

, 1702 09 15 .9: 1530 57 1623.41 16.50 1509.57 1603.45 :598.13 1509.89 1502 21 :GL90 1487 94 1473 29 r ese.90 847.02 “ 8.30 90 8.30 % 19471 76 69 660 63 CA .13 651. 644.73 632 43 6st.26 547.20 543 02 540.07 500.58 ale 7a 37.05 3703) 364.11 307.87 65,72 30,97 L-3.32

Explanation / Answer

0.96 ppm peak is for -CH3 proton of the bytyl part which appears as triplet due to the presence of two neighboring proton

1.6 and 1.4 ppm peaks are due to two -CH2-CH2- of the butyle portion . They will appear as multiplate

2ppm peak due to -CH3 of acetate part.It should appear as a singlet . The adjacent peak could be due to the unreacted acetic acid which you have used. 4ppm peak is due to the proton adjacent to ester group. It will appear as triplet.

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