Match each pair of compounds on the left and its corresponding melting points (m

Question

Match each pair of compounds on the left and its corresponding melting points (m. p.) or boiling points (b.p.) in degree C to a major reason, given on the right, why the physical property increases. Answers may be repeated. Remember that "di" means two. Interestingly, NH_2 (CH_2)_5 NH_2 is commonly known as cadaverine. NH_2 (CH_2)_5 NH_2 (b.p. 179), butane-1, 4-diol (b.p. 235) _ a. easier to rotate in place 2, 2-dimethylpropane-1, 3-diol (b.p. 208), pentane-1, 5-diol (b.p. 242) _ b. greater weight butan-1-ol (b.p. 118), CH_3 (CH_2)_3 (b.p. 131) _ c. more hydrogen bonds pentane-1, 5-diol (m.p. -18), 2, 2-dimethylpropane-1, 3-diol (m.p. 129) d. more polar bonds pentane-1, 5-diol (m.p. -18), NH_2 (CH_2)_5 NH_2 (m.p. 12) _ e. more van der Waal interactions Using the method that we learned in class to estimate specific gravities and given the following atomic weights (C 12. H = 1, N = 14, O = 16), which compound has a density closest to that of water?

Explanation / Answer

1. Matching the two columns

1. NH2(CH2)5NH2 (bp 179), butan-1,4-diol (dp 235)               :              c. more hydrogen bonds

2. 2,2,-dimethylpropane-1,3-diol (bp 208), pentane-1,5-diol (bp 242)   : d. more polar bonds

3. butan-1-ol (bp 118), CH3(CH2)3I (bp 131)                                        : e. more van der waals interaction

4. pentan-1,5-diol (mp -18), 2,2-dimethylpopane-1,3-diol (mp 129)      :  c. more hydrogen bonds

5. pentan-1,5-diol (mp -18), NH2(CH2)5NH2 (mp 12)                          :  b. greater weight

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