In the titration of 25.0 mL of 0.1 M CH_3COOH with 0.1 M NaOH, how is the pH cal
ID: 500824 • Letter: I
Question
In the titration of 25.0 mL of 0.1 M CH_3COOH with 0.1 M NaOH, how is the pH calculated after 8 mL of titrant is added? The pH is based on the concentration of protons present in the solution, which is equal to the original concentration of the base. The pH is calculated using the H-H equation for a buffer solution, using the ratio of the concentrations of the weak base and the weak acid, and the pK_a of the acid. The pH is 7. The pH is calculated by determining the concentration of weak conjugate base present in the solution, using an ICE table to calculate the hydroxide ion concentration present after hydrolysis, subtracting pOH from 14, and taking the negative log of the result. The pH is calculated by determining the concentration of leftover hydroxide ions in the solution, subtracting pOH from 14, and taking the negative log of the result. The pH is calculated by determining the concentration of weak conjugate acid present in the solution, using an ICE table to calculate the proton concentration present after hydrolysis, and taking the negative log of the result. The pH is 1. The pH is 14. The pH = pK_a of the acid.Explanation / Answer
The pH is calculated using the H-H equation for a buffer solution, using the ratio of the concentrations of the weak base and weak acid and the pka if the acid