Circle the intermolecular force that accounts for the following observations: a.

Question

Circle the intermolecular force that accounts for the following observations: a.hydrogen bonding dipole-dipole forces dispersion forces b. The boiling point of hydrogen (H_2) is -253 degree C but the boiling point of oxygen (O_2) is -183 degree C. hydrogen bonding dipole-dipole forces dispersion forces c. The boiling point of 1-carbon tetrachloride is 77 degree C but the boiling point of methane is -162 degree C. Answer: hydrogen bonding dipole-dipole forces dispersion forces d. The boiling point of methyl formate is 32 degree C but the boiling point of acetic acid is 118 degree C Answer: hydrogen bonding dipole-dipole forces dispersion forces

Explanation / Answer

Hydrogen bonding is always stronger than dipole dipoleinteractions

Dipole dipole interactions are stronger than dispersion forces

Which is the more stronger interactions that will have highest boiling point. This is the basic statement

A.

The difference in electronegativity of N-H is more than P-H

So ammonia can form stronger hydrogen bonding than phosphene

So ammonia will have higher boiling point than phosphene b

B.

Both H2 and O2 don't show dipole moment so baseed on size

O2 will be larger size so stronger dispersion forces

C.

Similarly c also ccl4 is larger size so mer dispersion forces

Because both are tetrahedral

D.

Acetic acid have hydrogen bonding where as methyl formate can have dipole interactions

Hydrogen bonding is stronger than dipole interactions

So acetic acid is having higher boiling point

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