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Partner Name Partner NN lume Data Mass of Beaker 1 Mass of Beaker 1 CaCl 08.0a M

ID: 503173 • Letter: P

Question

Partner Name Partner NN lume Data Mass of Beaker 1 Mass of Beaker 1 CaCl 08.0a Mass of Beaker 2 Mass of Beaker 2 Kuo Mass of Watch Glass Filter Paper Mass of watch Glass Filter Paper Cado)20after i" Heating) 7 57! Mass of Watch Glass Filter Paper ca (after 2" Heating 5T Mass of Beaker 2 Residue (after l'i Heating) Mass of Beaker 2 Residue (after 2nd Heating) Calculations (Sample Calculation Sheet will show all calculations below 1. Mass of CaCl2 used 2. Mass of KIO3 used 3. Mass of Ca produced 4. Molar Mass of Caci 5. Molar Mass of KIOs 6. Molar Mass of CafIO3) 7. Molar Mass of KCI 8, Moles of CaCl used 9. Moles of KIO3 used 10. Moles of Ca(o, produced l 1. Theoretical Yield (g) of Ca(IOs)2 based on CaCl2 used

Explanation / Answer

Balanced reaction taking place is:

CaCl2 + 2KIO3 ----> Ca(IO3)2 + 2KCl

Calculations:

Mass of CaCl2 used = 119.878-118.742 = 1.136 g

Mass of KIO3 used = 109.260-108.096 = 1.164 g

Mass of Ca(IO3)2 produced = 79.572-78.533 = 1.039 g

Molar mass of CaCl2 = 111 g

Molar mass of KIO3 = 214 g

Molar mass of Ca(IO3)2 = 390 g

Molar mass of KCl = 74.55 g

Moles of CaCl2 used = 1.136/111 = 0.010234

Moles of KIO3 used = 1.164/214 = 0.00543

Theoretical yield based on CaCl2 used = 0.010234*111 = 1.1359 g

Theoretical yield based on KIO3 used = 0.00543*0.5*214 = 0.581 g