Part A; The reactant concentration in a first-order reaction was 0.100 M after 5

Question

Part A;

The reactant concentration in a first-order reaction was 0.100 M after 50.0 s and 1.70×103M after 100 s . What is the rate constant for this reaction?

Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash.

Part B:

The reactant concentration in a second-order reaction was 0.880 Mafter 255 s and 9.00×102M after 845 s . What is the rate constant for this reaction?

Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash.

Explanation / Answer

PART(A)
Rate = change in concentration / change in time

r = - (0.00170 - 0.100) / (100 - 50.0)

r = 0.00197 M/s

We know that, according to law of mass action,

rate = k [reactant]

0.00197 = k (0.100)

k = 0.0197 s-1

PART(B)

Rate = - (0.0900 - 0.880) / (845 - 255)

r = 0.00134 M/s

And

Rate = k[reactant]2

0.00134 = k (0.880)

k = 0.00152 L.mol-1.s-1

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects