Map Sapling Learning this question has been customized by Pamela Mills at City U

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Map Sapling Learning this question has been customized by Pamela Mills at City University of New York (CUNY, Lehman Colleg What's the boiling point water at the top of Mt Everest Thermodynamic (atmospheric pressure 0.54 atm)? Table at 250c Substance (kJ/mol) (J/mol-K) (kJlmol) H,oli) H,ole) -237.1 285.8 70.0 H2O(l) -241.8 188.8 -228.6 H20 (g) Number Incorrect. Tbm 84.45 The standard change in Gibbs energy for a reaction is AG ,a znAGr (products)-EmAGr (reactants) where AGr is the standard molar Gibbs energy of formation, and n and m are coefficients from the chemical reaction. A Previous 8 Give Up & view solution Try Again Next Exit

Explanation / Answer

Apply:

ln(P2/P1) = dH/R*(1/T1-1/T2)

we need dH

dH = Hvap -Hliq = -241.8 - -285.8 = -44 kJ/mol approx

so

we know that

T = 100C = 373 K, at P = 1 atm

for P = 0.54 atm

then

ln(0.54/1) = 44000/8.314*(1/373-1/T2)

solve for T2

-1/T2 = ln(0.54/1) * 8.314 / 44000 - 1/373

T2 = -(-0.0027973)^-1

T2 = 357.487 K

T2 = 357.487-273

T2 = 84.487 °C

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