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ID: 504005 • Letter: T
Question
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1)
Ka of HF = 7.20 x 10^-4
Kb of F- = Kw / Ka
Kb = 1.0 x 10^-14 / 7.20 x 10^-4
Kb = 1.39 x 10^-11
2)
C9H7N + H2O ----------------------------> C9H7NH+ + OH-
3)
aspirin Ka = 3.0 x 10^-4
pH = 1/2 [pKa - logC]
pH = 1/2 [3.52 - log 0.539]
pH = 1.89
pH + pOH = 14
pOH = 12.1