The number of moles of a solid that dissolves in 1 liter of water is called the

Question

The number of moles of a solid that dissolves in 1 liter of water is called the molar solubility. For Mn_3(PO_4)_2, the molar solubility is 4.0 times 10^-5 M. What is the K_sp for this compound? 0.25 moles of MgCl_2 and 1.0 mole of NaOH are in water with a final volume of 1 L. The K_sp of Mg(OH)_2 is 5.6 times 10^-12. What is the final concentration of OH^- and Mg^2+ at the equilibrium? What is the molar solubility of Mg(OH)_2 in an aqueous solution? What is the final concentration of the OH^- of Mg(OH)_2 in an aqueous solution of 0.10 M MgCl_2?

Explanation / Answer

Q1.

Mn3(PO4)2 <--> 3Mn+2 + 2PO4-3

Ksp = [Mn+2]^3[PO4-3]^2

1 mol of Mn3(PO4)2 --> 3 mol of Mn+2 and 2 mol ofPO4-3

so

[Mn+2] = 3*(4*10^-15)

[PO4-3] = 2*(4*10^-15)

Ksp = [Mn+2]^3[PO4-3]^2

Ksp = (3*(4*10^-15))^3(2*(4*10^-15))^2

Ksp = 1.1059*10^-70

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