Phosphorus pentachloride, PCl_5 dissociates to form PCl_3 (g) and Cl_2 (g) PCl_5

Question

Phosphorus pentachloride, PCl_5 dissociates to form PCl_3 (g) and Cl_2 (g) PCl_5 (g) doubleheadarrow PCl_3 (g) + Cl_2 (g) Initially, 0.84 mol of PCl_5 (g) and 0.18 mol of Cl_2 (g) are mixed in a 1.00 L container. When the system has reached equilibrium there are 0.74 mol of PCl_5. What is the value of K_c? Under certain conditions, nitrogen, N_2, and oxygen, O_2, react to form nitrogen oxide NO. Suppose that 0.360 NO M is placed in a reaction and allowed to decompose to form N_2 (g) and O_2 (g) at 2500 K K_c = 2.1 10^-3. What will be the concentration of N_2, O_2 and NO at equilibrium? N_2 (g) + O_2 (g) doubleheadarrow 2 NO (g)

Explanation / Answer

6)

[PCl5]= 0.84mol/1L =0.84M

[Cl2]0 = 0.18mol/1.00L = 0.18M

PCl5 -----> PCl3 + Cl2

Initial    0.84M                0            0.18M

Change –x                        +x          0.18+x

Equilibrium 0.74M          0.10       0.18 +0.10

Kc =       [PCl3][Cl2]/[PCl5]                                                                       

Kc = 0.10 x 0.28/0.74

= 0.0378

  

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