Mimi’s daily caloric consumption consists of three meals: Breakfast: 173 kcal; 1
ID: 506419 • Letter: M
Question
Mimi’s daily caloric consumption consists of three meals:
Breakfast: 173 kcal; 12 g protein, 20 g carbohydrates, 5 g fat
Lunch: 254 kcal, 15 g protein, 26 g carbohydrates, 10 g fat
Dinner: 417 kcal; 8 g protein, 40 g carbohydrates, 25 g fat
a) Determine the percentage of Mimi’s daily caloric consumption from fat.
(2 points)
b) Mimi is a very busy person. She is enrolled in 6 courses at U of Tampa and doesn’t have much time to exercise during the week because she spends most of her time studying. At rest, Mimi burns 1200 kcal/ day. If she eats the same food items for all three meals, how much fat does she lose from her sedentary lifestyle over the semester (90 days)?
Explanation / Answer
a)
Fat --> 1 g of fat --< 9 kcal so
total fat per day --> 5g + 10g + 25 g =40 g of fat
Eenergy from fat = 9*40--> 360 kcal from fat
B)
Erest -1200 kcal/day
find how much fat she loses...
Etota ( all food ) = 173 +254+417 = 844 kcal per day
dE = 844 - 1200 = -356 kcal/day
fat lost --> 356/9 = 39.55 grams of fat lost per day
T = 90 days --> 39.55 g of fat / day *90 days = 3559.5 grams of fat lost in 90 days --> 3.5 kg of fat lost in the semester