The solution of Malonitrile in ether is 30 g per 100 mL and in water @ room temp

Question

The solution of Malonitrile in ether is 30 g per 100 mL and in water @ room temperature is 19.95 g per 100 mL. Suppose a reaction mixture when diluted with water afforded 500mL of an aqueous solution of 25 g of the reaction product malonitrile, CH_2(CH)_2 which is to be isolated by extraction with ether. a) What is K_D -- Distribution coefficient? b) What Weight of Malonitrile would be recovered by extraction with one-500mL of ether? - SHOW YOUR CALCULATION CLEARLY c) What weight of Malonitrile would be recovered by 4-12SmL of ether? SHOW YOUR WORK CLEARLY

Explanation / Answer

(a) Use the information given directly

K = (30/19.95) = 1.5

(b)

K = (x/500) / [(25-x) / 500] = 1.5

x = 15 g in ether layer

25 - x = 25 -15 = 10 g in water layer

(c)

you will do the same thing, only your first equation would be

K = 1.5 = (x/125) / [(25- x) / 500] and solve for x

x = 6.81 g in ether layer

25 - x = 25 - 6.81 = 18.18 g in water layer

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---