Consider the equilibrium: heat + 4NH 3(g) + 5O 2(g) = 4NO (g) + 6H 2 O (g). Cert
ID: 512263 • Letter: C
Question
Consider the equilibrium: heat + 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O(g). Certain changes are made on this system(see left column).Considering each change separetly, state the effect ( increase, decrease, or no change) that the change has on the original equilibrium value of the quantity listed in the center column. The temperature and volume remain constant unless otherwise noted.
Change Equilibrium Value Effect
Add NO number of moles of H2O
Add NO number of moles of O2
Remove NO number of moles of NH3
Add heat number of moles of NO
Add O2 number of moles of NH3
Remove heat number of moles of NH3
Remove NH3 number of moles of H2O
Add O2 heat content(temperature)
Add H2O heat content(temperature)
Add NH3 number of moles of H2O
Explanation / Answer
heat + 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O(g)
Change Equilibrium Value Effect
Add NO number of moles of H2O decrease
Add NO number of moles of O2 increase
Remove NO number of moles of NH3 decrease
Add heat number of moles of NO increase
Add O2 number of moles of NH3 decrease
Remove heat number of moles of NH3 increase
Remove NH3 number of moles of H2O decrease
Add O2 heat content(temperature) no change
Add H2O heat content(temperature) no change
Add NH3 number of moles of H2O increase