Why is [Ca(OH)2] not included in the expression for Ksp? a). Pure solids are not
ID: 513288 • Letter: W
Question
Why is [Ca(OH)2] not included in the expression for Ksp?a). Pure solids are not included in equilibrium expressions. b). Ionic compounds are not included in equilibrium expressions. c). Reactants are not included in equilibrium expressions. d) Strong bases are not included in equilibrium expressions.
Why is [Ca(OH)2] not included in the expression for Ksp?
a). Pure solids are not included in equilibrium expressions. b). Ionic compounds are not included in equilibrium expressions. c). Reactants are not included in equilibrium expressions. d) Strong bases are not included in equilibrium expressions.
a). Pure solids are not included in equilibrium expressions. b). Ionic compounds are not included in equilibrium expressions. c). Reactants are not included in equilibrium expressions. d) Strong bases are not included in equilibrium expressions.
Explanation / Answer
Note that Ca(OH)2 is a solid
so, the best answer is
a). Pure solids are not included in equilibrium expressions.
Since they have activity = 1, no need to add them