Need help with a lab. Needing help with finishing the table. Trial 1 Trial 2 Tri

Question

Need help with a lab.

Needing help with finishing the table.

Trial 1

Trial 2

Trial 3

Trial 4

Table 2 Hot Sauce & Ketchup Titration Mass of Sauce (grams) Concentration of NaOH Used (M) (ml)NaOH needed to reach equivalence point (mol) NaOH needed to reach equivalence point [show work below) Concentration of C2H402 (mol/g of sauce) ishow work belowl Average Concentration of C2H402 (mol g of sauce) pH of solution at equivalence point NaOH needed to reach half-equivalence point (mL) pH of solution at half- equivalence point Hot Sauce Trial 1 Hot Sauce Trial 2 Ketchup Trial 1 Ketchup Trial 2 1.5g 1.5g 1.5g 1.5g 1 1 6ml 5.5ml 3ml 3.25ml 726pl 5.71 pH 5.53pH 7.42 pH 3ml 2.5ml 1.5ml 1.5ml 4.67pH 4.62 pH 4.98 pH 4.82 pH

Explanation / Answer

density= mass/ volume

so mass= density* volume= 2.13*6= 12. 78 g

moles= weight/molecular weightt = 12.78/ 40 = 0.3195 mol

number of moles of NaOH = 0.3195 moles    trail1

= 0.2928 moles trail 2

= 0.159 moles trail3

= 0.186 moles trail 4

concentration of CH3COOH in 1. 5g= 1.5/60.05= 0.0249 moles

M = n*1000/volume= 0.0249mole/L

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