For the following example, identify the following. H_2C(l) rightarrow H_2O(x) A)
ID: 518032 • Letter: F
Question
For the following example, identify the following. H_2C(l) rightarrow H_2O(x) A) a positive Delta H and a negative Delta S B.) a positive Delta H ad a positive Delta S C) a negative Delta H and a positive Delta S D) a negative Delta H and a negative Delta S E) It is not possible to determine without more information. Use the standard half-cell potential listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 degree C. (The equation is balanced.) Pb(s) + Br_2(l) rightarrow Pb2+(aq) + 2 Br^- (aq) Pb^2+(aq) + 2 e^- rightarrow Pb(s) E degree = -0.13 V Br_2(l) + 2 e^- rightarrow 2 Br^-(aq) E degree = + 1.07 V A) -0.60 V B) -0.94 V C) +0.94 V D) + 120 V E) -1.20 V Which of the following reactions would have the smallest value of K at 298 K? A) A + B rightarrow 3C E degree cell = +0.15 V B) A + B rightarrow C E degree cell = +1.22 V C) A + B rightarrow 2 C; E degree cell = -0.030 V D) A + 2B rightarrow C; E degree cell = +0.98 V E) More information is needed to determine. Calculate Delta G_rxn at 298 K under the conditions shown below for the following reaction. 3O_2(g) rightarrow 2 Q_3(g) Delta G degree = +326 kJ P(O_2) = 0.41 atm, P(O_3) = 52 atm A) -47.4 kj B) + 332 kj C) +341 kj D) -109kJ E) + 17.8 kJExplanation / Answer
1. when liquid water become Solid water
cooling oberves means it is endothermic reaction.
means delta H=+ve
when liquid become solid, disorderness of molecule decreses and so delta S decreses.so delta S= -ve
option A
2. E0=Ecathode-Eanode=1.07+0.13= +1.20
3.delta G= -nFE0 =-RTlnK
option = B
E0 directly propotional to K
so one with higher E0 have higher K value.