Part A: Co2+ Express your answer in condensed form in order of increasing orbita

Question

Part A: Co2+ Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Part B: Tc3+ Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Part C: Os4+ Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Explanation / Answer

A)

cobalt has 25 electron

condensed --> [Ar] 3d5 4s2

after losing 2 electrons -->

[Ar] 3d5

B)

Tc = 43 electrons, so

Tc3+ --> [Kr] 4d5 5s2

after losing 3 electrons --> [Kr] 4d4

C)

Os = 76 electrons so

[Xe] 4f14 5d6 6s2

remove 4 electrons, 2 from s and 2 from d

Os4+ -->[Xe] 4f14 5d6 6s2 -->

[Xe] 4f14 5d4

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects