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Identify the reactant that is a Bronsted-Lowry acid and the reactant that is a B

ID: 520562 • Letter: I

Question

Identify the reactant that is a Bronsted-Lowry acid and the reactant that is a Bronsted-Lowry base in each of the following: Part A H_2SO_4(aq) + H_2O(l) rightarrow H_3O^+ (aq) + HSO_4^-(aq) H_2SO_4 is the acid (proton acceptor). H_2O is the base (proton donor). H_2O is the acid (proton acceptor), H_2SO_4 is the base (proton donor). H_2O is the acid (proton donor), H_2SO_4 is the base (proton acceptor). H_2SO_4 is the acid (proton donor), H_2O is the base (proton acceptor). Part B F^- (aq) + H_2O(l) HF(aq) + OH^- (aq) H_2O is the acid (proton donor): F^- is the base (proton acceptor). F^- is the acid (proton donor): H_2O is the base (proton acceptor). H_2O is the acid (proton acceptor): F^- is the base (proton donor). F^- is the acid (proton acceptor) H_2O is the base (proton donor). Part C H_2S (aq) + CH_3 - CH_2 - NH_2(l) HS^- (aq) + CH_3 -CH_2 -NH_3^+ (aq) H_2S is the acid (proton acceptor): CH_3 - CH_2 - NH_2 is the acid (proton acceptor); H_2S is the base (proton donor). CH_3 -CH_2-NH_2 is the acid (proton acceptor) H_2S is the base (proton donor). H_2S is the acid (proton donor): NH_2 is the base (proton acceptor. CH_3-CH_2-NH_2 is the acid (proton donor): H2_S is the base (proton acceptor).

Explanation / Answer

A Brønsted-Lowry acid is a proton (hydrogen ion) donor.

A Brønsted-Lowry base is a proton (hydrogen ion) acceptor.

Part A.

In this reaction H2SO4 donates proton to H2O. Hence H2SO4 is a brownsted acid. Whereas H2O accepts proton, hence it is Brønsted-Lowry base (option 4)

Part B. In this reaction H2O donates proton (brownsted acid) and F- accepts proton (Brønsted-Lowry base) to for HF and oh-. (option 1 is correct)

Part C. Here H2S is proton donor (brownsted acid) to form HS- and CH3-CH2-NH2 accepts proton to form CH3-CH2-NH3+(brownsted base) option (3 is correct)