The solubility of a substance is the quantity that dissolves to form a saturated

Question

The solubility of a substance is the quantity that dissolves to form a saturated solution, and it can be represented by the solubility product expression (K_sp). The solubility product expression is equivalent to the product of the ion concentrations after each is raised to a power that is equal to its coefficient in the balanced equilibrium equation. For an example, see the following reaction involving calcium phosphate and its corresponding solubility product expression: Ca_3 (PO_4)_2 (s) 3Ca^2+ (aq) + 2PO_4^3- (aq) K_sp = [Ca^2+]^3 [PO_4^3-]^2 The molar solubility (S) of a slightly soluble salt is the number of moles of solute that dissolve in 1 L of solution and has the units M. For the example above, every 1 mol of solute that dissolves produces 3 mol of Ca^2+ and 2 mol of PO_4^3-, so the molar solubility is equivalent to S = [Ca^2+]/3 = [PO_4^3-]/2 If MgCrO_4 were added to water to form 1 L of solution, the concentration of which species will be equal to the molar solubility? Check all that apply. Mg^2+ CrO_4^2- MgCrO_4

Explanation / Answer

MgCrO4 (s) ----------------> Mg+2 (aq) + CrO42-

                                             S                  S

KsP = [Mg+2][CrO42-]

Ksp = s*s

Ksp   = s2

s     = squar root Ksp

solubility of each species

S   = [Mg+2]

S   = [CrO42-]

[MgCrO4] = 0

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---